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 03-12-2010, 11:02 AM #1 happymat27 Subscriber     Join Date: Jul 2004 Posts: 1,257 MEL headache! Hi, it's been an age since I've posted up here but I need a little help with MEL and I figured that this would be the place to ask. So... Imagine a curve with an unknown number of CV's, I have made a script to count the CV's and attach a cluster to each one. I now need to distribute the clusters along the X axis using 0.005 as a base and the sequence 1,2,4,8,16,32,64....etc as the multiplier. So the first cluster would be at 0.005, the second at 0.010, the third at 0.020, the fourth at 0.040 and so on. has anyone got an idea how I could achieve this with MEL? Cheers, Mat __________________ Click here to visit my site
 03-12-2010, 02:49 PM #2 gster123 Moderator     Join Date: May 2005 Location: Manchester Uk Posts: 6,300 Hi Mat, Hows things, not seen you about for ages? You could use a if loop, create a variable that contains the start number, then set it for the end and what you need \$varible = whatever it is ; if (\$variable < final number) { Do something ; \$variable += increment number ; } with the above I think I may have mixed up between MEL and C# at some points! But the theory should work __________________ "No pressure, no diamonds" Thomas Carlyle
 03-12-2010, 03:25 PM #3 happymat27 Subscriber     Join Date: Jul 2004 Posts: 1,257 Hey Steve, yeah all is good thanks... working hard etc. what about yourself, still at the Uni? So yeah MEL, or any other programming language, has never been my forte but I've got this script..... // counting the CV's in the curve string \$curve = "waveCurveShape"; int \$numSpans = `getAttr ( \$curve + ".spans" )`; int \$degree = `getAttr ( \$curve + ".degree" )`; int \$numCVs = \$numSpans + \$degree; // this just lets me know how many there are print \$numCVs; // a cluster for each CV for (\$i=0; \$i<=(\$numCVs - 1); \$i++) { select -r waveCurve.cv[\$i]; newCluster " -envelope 1"; } // rename and group clusters for (\$i=1; \$i<(\$numCVs +1); \$i++) { rename ("cluster" +\$i +("Handle")) ("waveCluster" +\$i); } //group clusters to neaten the outliner for (\$i=1; \$i<(\$numCVs +1); \$i++) { select -add ("waveCluster" +\$i); } group; xform -os -piv 0 0 0; rename group1 clusterGroup; Create any curve and call it waveCurve and then execute the script, it will count the CV's and then create a cluster for each CV. I can move the clusters one at a time to wherever I want using the CV count (\$numCVs) for instance..... // sets the location in x to the number of cluster -1 for (\$i=1; \$i<(\$numCVs +1); \$i++) { float \$c = (\$i-1); select -r ("waveCluster" + \$i); move -rpr (\$c) 0 0; } So waveCluster1 will be at 0,0,0 then waveCluster2 wil be at 1,0,0 etc. I need the X value to follow the number pattern... 0,1,2,4,8,16,32,64,128.... etc for however many verts/clusters there are in the curve but my MEL-ness is not anywhere near that standard!! Got any ideas? Hope you're well, Mat __________________ Click here to visit my site Last edited by happymat27; 03-12-2010 at 03:28 PM.
 03-12-2010, 05:53 PM #4 stwert EduSciVis-er   Join Date: Dec 2005 Location: Toronto Posts: 3,374 for (\$i=0; \$i<(\$numCVs); \$i++){ float \$c = (\$i-1); select -r ("waveCluster" + 2^\$i); } ...like that? Actually I'm not sure what the interior stuff should be, but the function would be 2^\$i. __________________ -stwert Website - Blog - YouTube - Vimeo - Facebook - Twitter -->How to Effectively Ask Questions on Forums<--
 03-12-2010, 09:19 PM #5 happymat27 Subscriber     Join Date: Jul 2004 Posts: 1,257 Cheers for your thoughts, I got it sorted..... int \$i; float \$x = 0.005; for(\$i = 0; \$i < \$numberOfCVs; \$i++) { \$x *= 2; // Do whatever needs to be done } Thanks to kbrown for that Doubtless I'll be back again soon when I next get stuck!! Cheers, Mat __________________ Click here to visit my site
 05-12-2010, 09:43 AM #6 gster123 Moderator     Join Date: May 2005 Location: Manchester Uk Posts: 6,300 Hi Mat, Yeas still there, going ok really. How about yourself? I'll mail you. Cheers Steve __________________ "No pressure, no diamonds" Thomas Carlyle

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